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References to generic type AddLinkEntry Class should be parameterized, Why is Collection not simply treated as Collection. In principle, you can choose whether you want to use the pre-defined generic collections in their parameterized or raw form. Does Java support default parameter values? Difference between StringBuilder and StringBuffer, Initialization of an ArrayList in one line, Difference between "wait()" vs "sleep()" in Java, How to fix java.lang.UnsupportedClassVersionError: Unsupported major.minor version. How about saving the world? Thanks. ArrayList<ArrayList<Character>> adj = new ArrayList<> (); Share. What woodwind & brass instruments are most air efficient? How to resolve `Raw use of parameterized class 'Comparable'` warning Each element represents an Amenity in an apartment inspection. References to generic type ArrayList<E> should be parameterized 4. A raw type is a name for a generic interface or class without its type argument: List list = new ArrayList (); // raw type Instead of: List<Integer> listIntgrs = new ArrayList <> (); // parameterized type List<Integer> is a parameterized type of interface List<E> while List is a raw type of interface List<E>. [Solved] Raw use of parameterized class | 9to5Answer What is a serialVersionUID and why should I use it? We are a java shop, and the kotlin is confusing some programmers, so I'm going through and converting it all to Java. Java warning - JList is a raw type, references must be parameterized Not the answer you're looking for? List names = new ArrayList (); // warning: raw type! IntelliJ provide an inspection name Raw use of parameterized class. // a parameterized (generic) class public class Name<TypeVar, ., TypeVar> {-Convention 1-letter name such as Tfor Type , Efor Element,Nfor Number , Kfor Key , Vfor Value , or Mfor Murder The class's code refers to the type parameter -e.g., E To instantiate the abstraction, a client supplies type arguments -e.g., String as in . Parabolic, suborbital and ballistic trajectories all follow elliptic paths. What is a raw type and why shouldn't we use it? The erasure of a constructor or method signature s is a signature consisting of the same name as s and the erasures of all the formal parameter types given in s. The return type of a method (8.4.5) and the type parameters of a generic method or constructor (8.4.4, 8.8.4) also undergo erasure if the method or constructor's signature is erased. The code is working fine, but I am getting "raw use of parameterized class" warning on line: The issue is that type parameter T can be generic type. Otherwise, the compiler is unable to help you verify that the types are actually compatible in all scenarii. Asking for help, clarification, or responding to other answers. In contrast to arrays where all this is a runtime thing: The above compiles. Item 26: Don't use raw types First, a few terms.